So, it turns out your classmate was correct. The reference that I used in class for determining whether a year is a leap year was incorrect. The **article found here** gives the correct rules for determining a leap year. You can read it on your own for more information.

In any case, I have written an accurate version of the program we were intending to implement that does correctly decide if a year is a leap year. Please use this code to update your program.

# leapyear.py # Rules for a leap year (see: http://www.infoplease.com/spot/leapyear2.html) # 1. Most years that can be divided evenly by 4 are leap years. # (For example, 2012 divided by 4 = 503: Leap year!) # 2. Exception: Century years are NOT leap years UNLESS they can be evenly # divided by 400. (For example, 1700, 1800, and 1900 were not leap years, # but 1600 and 2000, which are divisible by 400, were.) # Note: Including \n in a string inserts a new (blank) line in the display. print('\n********************') print('Leap Year Calculator') print('********************') print('This program will tell you if the year you enter is a leap year.') yearstr = raw_input('Enter a year: ') year = int(yearstr) # First check to see if your year is not divisible by 100 but divisible by 4.ifyear % 100 != 0 and year % 4 == 0: # Yes print('Yes, ' + yearstr + ' is a leapyear.') # Now check to see if your year is divisible by 100 and 400.elifyear % 100 ==0 and year % 400 == 0: # Also Yes print('Yes, ' + yearstr + ' is a leapyear.') # Otherwise, it is not a leap year.else: print('No, ' + yearstr + ' is not a leap year.') print('\nDone.')